ajax - Basic PHP Class Creation Cause Parse Error: Parse Error

Solution:

Class method definitions are not statements, and therefore should not be terminated with{-code-1}.

This means that the}{-code-1} on lines 11, 16 and 17 should simply be} instead.

On another note, I don't know what version of PHP you're using. I'm using PHP 5.5 and got a very clear message:

Parse error: syntax error, unexpected '{-code-1}', expecting function (T_FUNCTION) in test.php on line 11

Solution:

It's always good to practice on simple examples to make its own idea about how it works.

This might help to clarify things.

class test
{
    public $x; 
    private $y; 

    function __construct() {
        echo "-- Constructor --<br/>";
        $this->changeX(1);
        $this->changeY(2);
        echo "-- Exiting Constructor --<br/>";
    }   

    public function changeX($val) {
        $this->x = $val;
        echo "X-->".$this->x."<br/>"; // for debugging purpose only
    }   

    private function changeY($val) {
        $this->y = $val;
        echo "Y-->".$this->y."<br/>"; // for debugging purpose only
    }   

    public function changeYprivate($val) {
        $this->changeY($val); // can call private method here
    }   

    public function getY() {
        return $this->y;
    }   
}  

  $objTest = new test();

  echo "X is ".$objTest->x." and Y is ".$objTest->getY()."<br/>";
  $objTest->changeX(3);
  $objTest->x = 10; // ok x is public, it can be modified
  $objTest->changeYprivate(4);

  // $a->changeY(4); // Error : cannot call this function outside the class !
  // $objTest->y = 20; // Error : y is private !
  // echo $objTest->y; // Error ! Can't even read y because it's private

  echo "X is ".$objTest->x." and Y is ".$objTest->getY()."<br/>";
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Output:

-- Constructor --
X-->1
Y-->2
-- Exiting Constructor --
X is 1 and Y is 2
X-->3
Y-->4
X is 10 and Y is 4
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