Get variable data outside from the Switch Statement in PHP

Solution:

Variable declared insideswitch statement is visible outside, of course.

Problem is when isn't declared inside switch, you can avoid it two ways:

1. $userid = 'default value'; beforeswitch
   
2. echo isset($userid) ? $userid : 'default value'; afterswitch.

Default value can be whatever, if nothing, use empty string.

Solution:

On possible way is to declare the variable before you call the switch statement.

$userid = "";
switch (some condition){
   case 1:
   $userid = $receiver->getMessage();
   break;
   case 2:
   break;
 }

 echo $userid;
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Solution:

You're not doing anything with case 2 or default. If you structure it like this, then it should work.

switch ($condition) {
  case 1:
     $userId = $receiver->getMessage();
  break;
  case 2:
     $userId = $receiver->someOtherMessage();
  break;
  default:
     $userId = null;
  break;
}
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At a different point you can validate if the userId has actually been set as well.