How to get the name of the day in PHP using date?

Solution:

You can simplify this a lot without converting back and forth betweendate andstrtotime:

$year = date('Y');
$month = date('n');
$lastDay = date('t');

foreach (range(1, $lastDay) as $day) {
    echo date('D, j m Y', mktime(0, 0, 0, $month, $day, $year)), '<br>';
}
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See http://php.net/mktime.

Omitting implicit default values and condensing it a bit, you can in fact boil it down to:

foreach (range(1, date('t')) as $day) {
    echo date('D, j m Y', mktime(0, 0, 0, date('n'), $day)), '<br>';
}
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Mon, 1 04 2019
Tue, 2 04 2019
Wed, 3 04 2019
...
Tue, 30 04 2019
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Note that this code has a minuscule potential to break, should you execute it right at the second in which one month rolls over to the next, and thedate('n') anddate('t') functions happen to be called "in different months". To avoid that possibility entirely, make this operation atomic:

list($year, $month, $lastDay) = explode(' ', date('Y n t'));

foreach (range(1, $lastDay) as $day) {
    echo date('D, j m Y', mktime(0, 0, 0, $month, $day, $year)), '<br>';
}
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Solution:

The code below will print out what you need..

$date1 = date('Y-m-01');
$Maximum_Date = date('t', strtotime($date1));

for($Date = 1; $Date <= $Maximum_Date; $Date++)
{
    $thatDay = date('Y-m-'.$Date);
    $day = date('l, j', strtotime($thatDay));
    $Month = date('m', strtotime($thatDay));
    $Year = date('Y', strtotime($thatDay));

    echo $day . ' ' . $Month . ' ' . $Year . '<BR>';
}
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Output:

Monday, 1 04 2019
Tuesday, 2 04 2019
Wednesday, 3 04 2019
Thursday, 4 04 2019
Friday, 5 04 2019
...
...
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if you change this line

$day = date('l, j', strtotime($thatDay));
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TO

$day = date('l, jS', strtotime($thatDay));
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The output will be: Monday, 1st 04 2019

Solution:

Use:

$date1 = date('Y-m-01');
$Month = date('m', strtotime($date1));
$Year = date('Y', strtotime($date1));
$Maximum_Date = date('t', strtotime($date1));

for($Date = 1; $Date <= $Maximum_Date; $Date++){
  $DataDate = date("D-m-Y",strtotime($Year."-".$Month."-".$Date));
  echo $DataDate. '<br>';;
}
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Solution:

You should try like below.

$date1 = date('Y-m-01');
$Month = date('m', strtotime($date1));
$Year = date('Y', strtotime($date1));
$Maximum_Date = date('t', strtotime($date1));

$StartDate=$date1;
$EndDate=($Year."-".$Month."-".$Maximum_Date);
$EndDate=date('Y-m-d',strtotime($EndDate));

while(strtotime($EndDate)>=strtotime($StartDate))
{
    echo date('l, d-m-Y',strtotime($StartDate))."<br/>";
    $StartDate=date('Y-m-d', strtotime($StartDate . ' +1 day'));
}
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After execute you will get result like below.

Monday, 01-04-2019
Tuesday, 02-04-2019
Wednesday, 03-04-2019
...................
...................
...................
...................
Saturday, 27-04-2019
Sunday, 28-04-2019
Monday, 29-04-2019
Tuesday, 30-04-2019
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Solution:

Add the following line to your loop:

    echo (new DateTime($Date. '-'. $Month .'-'. $Year))->format('l');
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It creates a new DateTime object with your data & echo's the day in the format that you requested.