javascript - Valid JSON to display data in angularJs

I want to display data(json) in my site using AngularJs . here's what i did :
Create a database in phpmyAdmin .
Create a table with 2 row , subject and body . Should i create an id ?
After doing with PHP and angular , I got JSON like this :

[{
    "0":"Soheil","subject":"Soheil",
    "1":"Sadeghbayan","body":"Sadeghbayan"}
    ,{"0":"","subject":"","1":"","body":""}
    ,{"0":"","subject":"","1":"","body":""}
    ,{"0":"dasdasd","subject":"dasdasd","1":"qe","body":"qe"}
    ,{"0":"Hello","subject":"Hello","1":"This is chandler !","body":"This is chandler !"}
    ,{"0":"","subject":"","1":"","body":""},
    {"0":"Something new in website","subject":"Something new in website","1":"oh Awsome !","body":"oh Awsome !"
}]
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I think this is invalid JSON because when I replace it with custom JSON that I wrote it work .

Json valid

{
    "fruits": [
        {
            "id": "1",
            "name": "Apple"
        },
        {
            "id": "2",
            "name": "Orange"
        }
    ]
}  
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AngularJS

var fruitsApp = angular.module('fruitsApp', []);

fruitsApp.factory('fruitsFactory', function($http) {
    return {
        getFruitsAsync: function(callback) {
            $http.get('fruits.json').success(callback);
        }
    };
});

fruitsApp.controller('fruitsController', function($scope, fruitsFactory) {
    fruitsFactory.getFruitsAsync(function(results) {
        console.log('fruitsController async returned value');
        $scope.fruits = results.fruits;
    });
});
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Html

<ul>
            <li ng-repeat="fruit in fruits">
                {{fruit.subject}} is {{fruit.body}}
            </li>
</ul>  
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php

    include('config.php');



$data = json_decode(file_get_contents("php://input"));
$subject = mysql_real_escape_string($data->subject);
$body = mysql_real_escape_string($data->body);
mysql_select_db("angular") or die(mysql_error());
mysql_query("INSERT INTO newstory (subject,body) VALUES ('$subject', '$body')");
Print "Your information has been successfully added to the database.";



$query = "SELECT * FROM newstory";
$result = mysql_query($query);

$arr = array();
while ($row = mysql_fetch_array($result)) {
    $subject = $row['subject'];
    $body = $row['body'];
    $arr[] = $row;
}
echo json_encode($arr);
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Any idea ? Thx in advance