php get array values as new variable for ldap

907

suppose I got an array like this:

array ([0] => array([0]=>dog [1]=>cat))

How am I able to get just only "dog" and "cat" to store them in variables? I would like to use them for a further search. Like okay I find one array animals with these values, take each value to find arrays which describes the dog and cat races.

my try failed:

echo '<pre>';
foreach($result as $animals){

for($i=0;i<$animals;i++){
$find = animals[i];
$filter = "(objectClass=*)";
$show = array("race","subrace");
$animalSearch = ldap_search($ds, $find, $filter, $show) or die "...";
$animalInfos = ldap_get_entries($ds,$animalSearch) or die"shit";
print_r($animalInfos);
}

386

Answer

Solution:

as waterloomatt said, accessing multi arrays are the key and i think i pretended his suggestions wrong. finally i got a solution:

$filter = "(description=just animals)";
$attr = array("name");
$search = ldap_search($ds, $dn, $filter, $attr) or die("not successfull");

$info = ldap_get_entries($ds, $search) or die ("no entries");

echo '<pre>';
foreach($info as $animals => $values){

          foreach($values as $newDn) {
              for ($i = 0; $i < count($newDn); $i++) {
                  echo $newDn[$i];
                  $RaceFilter = "(objectClass=*)";
                  $justthese = array("name", "color");
                  $raceSearch = ldap_search($ds, $newDn[$i], $RaceFilter, $justthese) or die("can't search");
                  $race = ldap_get_entries($ds, $raceSearch) or die ("no entries");

                  print_r($race);

              }
          }
    }

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