php - Get the value that comes after the ? operator in the URL

354

I want to get the value that will come after the '?' operator, for example:

www.blabla.com/any.php?h r u

I want to get this value "h r u", and to search this key in my database. I've already tried this:

$_SERVER["QUERY_STRING"]

This function is working fine but when I searched these values it prints like this "h%20r%20u" in my database from this query:

$query="SELECT * FROM databasename WHERE colum LIKE'%$link%'";

It will print link this " h%20r%20u no record found " and my database can't find this value. How can i solve my problem?

461

Check out the urldecode function.

969

You should, as pointed out, useurldecode($string). For SQL Injections, just escape the value in your query:

$link = mysql_real_escape_string(urldecode($_SERVER["QUERY_STRING"]));
$query="SELECT * FROM databasename WHERE colum LIKE'%$link%'";

if you use mysql or mysqli to make queries. UsePDO::quote instead to escape if you use PDO.

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