php - Output just the background color, just an image or both together

On my template I have a field where the user(s) can choose and select a background for their site.

This is called from the IDbackground-one in an array.

My question is, how would I be able to output this into the head section of my CSS correctly if the users are only given the following options:

1) The choice of just a background color

background: #990000;

2) The choice of just a background image

background: url(../images/example.jpg) no-repeat top left scroll;

3) Or the choice of a background color and an image

background: #990000 url(../images/example.jpg) no-repeat top left scroll;

This is my current snippet of code to output the script into the css head section:

<?php $background = of_get_option('background-one'); {  
    if ($background['color'] || $background['image']) {
        echo 'body {
        background: ' . $background['color'] . ' url(' . $background['image']. ') ' .$background['repeat']. ' ' .$background['position']. ' ' .$background['attachment']. ';';
    }

    else if ($background['color']) {  
        echo 'body {
        background: ' . $background['color']. ';';
    }

    else if ($background['image']) {
        echo 'body {
        background: ' . 'url(' . $background['image']. ') ' .$background['repeat']. ' ' .$background['position']. ' ' .$background['attachment']. ';';
    };
}
?>
Copy code

But with that, the results are:

1) The choice of just a background color

background: #990000 url() no-repeat top left scroll;

2) The choice of just a background image

background:url(../images/example.jpg) no-repeat top left scroll;

3) Or the choice of a background color and an image

background: #990000 url(../images/example.jpg) no-repeat top left scroll;

As I'm fairly new to writing PHP, how would I re-work my snippet above to get the results I'm after?