php push to array from function

Solution:

I think you should pass the array by reference using&:

function f($ar = array(), &$gl = array())
{
    $gl[0] = array($ar[1]);
}

$globals = array();
$array_example = array('foo', 'bar');
f($array_example, $globals);
print_r($globals);
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Will give you:

Array
(
    [0] => Array
        (
            [0] => bar
        )

)
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Demo

Solution:

man first you should modify thefunction to return the value and assign the returned value for the value to be printed . you are print the$global and it is an emptyarray . so your code should be like this .

<?php
    function f($ar = array(), $gl = array()){
        $gl[0] = array($ar[1]);
        return $gl;
    }
    $globals=array();
    $array_example=array('foo', 'bar');

    $globals = f($array_example, $globals);
    print_r($globals); 

    // prints out Array ( [0] => Array ( [0] => bar ) )
?>
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Solution:

Function always works on locally variables, And you want to use their locally variable scope to out of function. Check with below code, I hope it will help you

function f($ar=array(), $gl=array()){
    return array($ar[1]);
}
$globals=array();
$array_example=array('foo', 'bar');
$tmpArray = f($array_example, $globals);
$globals[0]=$tmpArray;
print_r($globals); 
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