PHP show date2 if date1 passed


I need help on this..
I am new in php and dummy..

$displaydate = "";

$paydate1 = "23-10-2016";
$paydate2 = "23-11-2016";   
$paydate3 = "23-12-2016";    
$paydate4 = "23-01-2017";    
$paydate5 = "23-02-2017";   
$paydate6 = "23-03-2017";

if todaydate is 23-10-2016 then $displaydate = "$paydate2" until 22-11-2016. When 23-11-2016 then $displaydate = "$paydate3" and so on.

then results    
if the date is 23-10-2016 until 22-11-2016 $displaydate = "$paydate2"   
if the date is 23-11-2016 until 22-12-2016 $displaydate = "$paydate3"    
if the date is 23-12-2016 until 22-01-2016 $displaydate = "$paydate4"   
if the date is 23-01-2016 until 22-02-2016 $displaydate = "$paydate5"  
if the date is 23-02-2016 until 22-03-2016 $displaydate = "$paydate6"   

please help with the code...





Organize your data convenient so you can easy access it. Put your paydates it an array:

$paydate = ["23-10-2016","23-11-2016","23-12-2016","23-01-2017","23-02-2017","23-03-2017"];

UPDATED per your comment:

$payout1 = $this->data->paymentdate1; 
$payout2 = $this->data->paymentdate2; 
$payout3 = $this->data->paymentdate3; 
$payout4 = $this->data->paymentdate4; 
$payout5 = $this->data->paymentdate5; 
$payout6 = $this->data->paymentdate6; 

$paydate = [$payout1,$payout2,$payout3,$payout4,$payout5,$pa‌​yout6];

Transform the dates in an easy to sort format:

function trf_date($date)
    return date('Y-m-d', strtotime($date));
$paydate = array_map("trf_date", $paydate );

Sort the array to be sure we will get the dates in ascending order while looping.


Now loop through the array to find the first date higher then today:

foreach($paydate as $key=>$val){
   if($val > date('Y-m-d'))

$displaydate = ''; //initialize the output variable

//check to see if the last retrieved date meets the condition not to be in the past. 
//this is for the case all dates in the array are in the past
if(isset($paydate[$key]) && $paydate[$key] > date('Y-m-d'))
   $displaydate = $paydate[$key];

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