php - Why does the "echo" statement support outputting multiple arguments in a single line and the "echo" function does not?

264

In PHP you can output multiple arguments at once with theecho statement like this:

echo "Mangoes", " ", "are", " ", "tasty.";

When you try to do the same with theecho function like this:

echo("Mangoes", " ", "are", " ", "tasty.");

You get a error, why is this so?
Could this be because PHP wants you to use string concatenation instead of multiple arguments?

Thank you in advance.

148

Answer

Solution:

Because is not a function. The docs clearly state this:

echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want to pass more than one parameter to echo, the parameters must not be enclosed within parentheses.

Undefined answered

2022-07-30

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208

votes

Answer

Solution:

when you callecho() its mean you call the function ofecho(). The echo just has one parameterecho(_string_). SO when you include the , sign in the bracket of echo parameter, so it means you make echo function has more than one parameter. So you are not allowed to do like thisecho("Mangoes", " ", "are", " ", "tasty.");

Please see this http://www.w3schools.com/php/func_string_echo.asp

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